The inner diameter of a wooden cylindrical pipe is 24cm. outer diameter is 28cm. lenghth of pipe is 35cm. find mass of pipe if 1cm cube of wood weighs 3grams.
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Hi there!
♦ For Outer Cylinder :
Radius, R = D/2 = 28/2 = 14 cm
Height = 35 cm
♦ For Inner Cylinder :
Radius, r = d/2 = 24/2 = 12 cm
Height = 35 cm
Now,
Volume of pipe = Vol. of Outer - Vol. of Inner Cylinder
= πR²h - πr²h
= πh ( R² - r² )
= 22/7 × 35 [ 14² - 12² ]
= 5720 cm³
Now, it's Given :
1 cm³ Volume = 0.6 g
Thus,
Mass of 5720 cm³ volume = 5720 × 0.6 g
= 3. 432 kg
[ Thank you! for asking the question. ]
Hope it helps!
♦ For Outer Cylinder :
Radius, R = D/2 = 28/2 = 14 cm
Height = 35 cm
♦ For Inner Cylinder :
Radius, r = d/2 = 24/2 = 12 cm
Height = 35 cm
Now,
Volume of pipe = Vol. of Outer - Vol. of Inner Cylinder
= πR²h - πr²h
= πh ( R² - r² )
= 22/7 × 35 [ 14² - 12² ]
= 5720 cm³
Now, it's Given :
1 cm³ Volume = 0.6 g
Thus,
Mass of 5720 cm³ volume = 5720 × 0.6 g
= 3. 432 kg
[ Thank you! for asking the question. ]
Hope it helps!
hrushibh:
Thanks a ton.
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