Question

the inner diameter of circular well is 3.5 it is 10 deep (1) find its inner curved surface area (2)the cost of plastering this curved surface at the rate of rupees 40 per metre square​

Answer 1

Answer:

(1) 220 m²

(2) ₹ 8,800

Step-by-step explanation:

Given,

Inner diameter of the well = 3.5 m

Height of the well = 10 m

(1) Inner CSA of the cylindrical well = 2πrh

                                                           = 2 x (22/7) x 3.5 x 10 m²

                                                           = 220 m²

(2) Cost of plastering the inner CSA = ₹ (220 x 40)

                                                            = ₹ 8,800

Hope it helps you....

Answer 2

Step-by-step explanation:

inner CSA = 2πrh

= 2*22/7*3.5/2*10

=2*22/7*35/20*10

=110

cost of plastering =40*110

=4400 rupees