the inner diameter of the cylindrical wooden pipe is 24 cm and its outer diameter is 28 CM the length of wooden pipe is 35 cm find the total surface area of the pipe
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inner diameter D1 = 24cm , R1= 12cm
outer diameter D2= 28cm , R2= 14cm
length of pipe H = 35CM
Total surface area = 2piR1H+2piR2H
=2piH(R1+R2)
=2*22/7*35(12+14)
=5720cm square
therefore total surface area of pipe is 5720cm square.
outer diameter D2= 28cm , R2= 14cm
length of pipe H = 35CM
Total surface area = 2piR1H+2piR2H
=2piH(R1+R2)
=2*22/7*35(12+14)
=5720cm square
therefore total surface area of pipe is 5720cm square.
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