Math, asked by harshikaupadhyay187, 3 months ago

The inner
Is 3.5 m. The depth of the well is 15 m. Find the cost of plastering the
mner curved surface at the rate of 25 per m2
Raja painted the outer surface of a cuboidal box of dimensions 8 m x 7.5 m x 6m. Find the surface area
painted by him, if he did not paint the bottom of the box.​

Answers

Answered by ayushisinha700
0

Answer:

i.Ans- 110 m^2

ii.Ans- Rs 4400

Step-by-step explanation:

r= radius=23.5=1.75 , h= depth of the well=10m 

⇒Curved surface area 

=2πrh

=(2×722×1.75×10)m2=110m2

⇒(ii) Cost of plastering = Rs 40 per m2

The cost of plastering the curved surface = Rs (110×40)= Rs 4400.

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