Question

the inside of an open metal box with internal dimensions 25cm*18cm*15cm are mined with a paper.Find the area of paper required.

Answer 1

Answer:

$\red { Area \: of \: Paper \: required} \green {= 1740 \: cm^{2} }$

Step-by-step explanation:

$\blue { Dimensions \:0f \:an \: open \:metal \:box}$

$Length (l) = 25 \:cm , \: breadth (b) = 18\:cm ,\\height (h) = 15\:cm$

$Area \: of \: Paper \: required \\= Total \:surface \: area - top \:area \\= 2(lb+bh+hl) - lb \\= 2( 25\times 18 + 18 \times 15 + 25 \times 15 ) - 25 \times 18 \\= 2( 450 + 270 +375 ) - 450 \\= 2\times 1095 - 450 \\= 2190 - 450 \\= 1740 \: cm^{2}$

Therefore.,

$\red { Area \: of \: Paper \: required} \green {= 1740 \: cm^{2} }$

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Answer 2

total surface area of cuboid length =25 cm

breadth=18cm

height=15 cm

area of paper required = total surface area - top area

= 2(lb+bh+hl) - lb

=2(25*28+18*15+25*15)-25*1

=2(450+270+375) - 450

= 2* 1095-450

= 1740 cm²

pls mark brainliest