Question

the inside perimeter of a running tricks show in the figure is 400 metre the length of each of a strength for partition partition is 90 M and the end a semicircle if the trick is is 14 M and every where find the area of a trick also find the length of outside boundary of a trick

Answer 1

Answer:

488

Step-by-step explanation:

Solution:-

The inside perimeter of the track = 400 m

The total length of the two straight portions = 90 + 90 = 180 m

Therefore the length of the remaining portion = 400 - 180 = 220 m

Circumference of the two remaining semi-circular portions = πr + πr = 2πr

'r' is the radius.

⇒ 2πr = 220 

2 × 22/7 × r = 220 

44r = 220 × 7

r = (220 × 7)/44

r = 35 m

So, the radius of the circular portion of the outer running running track = 35 m + 14 m = 49 m

Area of the track = Area of the two rectangles of dimensions 90 × 14 + The area of the circular rings.

= 2 × 90 × 14 + 22/7 × {(49)² - (35)²}

= 2520 + 22/7 ×(2401 - 1225)

= 2520 + (22 × 1176)/7

= 2520 + 25872/7

= 2520 + 3696

= 6216 sq m

Length of the outer running track = 2 × 90 + 2 × 22/7 × 49

= 180 + 308

Length of the outer running track = 488 m