Question

The instantaneous coordinates of a particle are x = (4t)m and y = (8t²)m. The acceleration of the particle is

Answer 1

use defferentiation mathod to get your required answer

here... net acc will be x + y = 0 + 16

Answer 2

Given :

Instantaneous coordinates of a particle are x = (4t) m and y = (8t²) m .

To Find :

The acceleration of the particle .

Solution :

We know , acceleration is equal to double differentiation of position of particle .

Therefore , acceleration towards x direction is :

$a_x=\dfrac{d^2(4t)}{dt^2}=\dfrac{d(4)}{dt}=0\ m/s^2$

Also , acceleration towards y direction is :  

$a_y=\dfrac{d^2(8t^2)}{dt^2}=\dfrac{d(16t)}{dt}=16\ m/s^2$

Therefore , the net acceleration of particle is $16\ m/s^2$ towards y direction .

Learn More :

Kinematics

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