The integers 5 and 15 are among a collection of 12 integers that form a group under multiplication modulo 56. list all 12.
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☆☆ranshsangwan☆☆
solution:-
It must include 1 since that's the identity.
5*15=19 so 19 is in the group.
5*19=39 so that's in the group.
5*39=27
5*27=23
5*23=3
5*3=15 so that doesn't help!
15*3=45
45*5=1 so that doesn't help.
5*5=25
39*39=9
39*3=5 which doesn't help.
45*9=13
So we have {1,3,5,9,13,15,19,23,25,27,39,45}.
solution:-
It must include 1 since that's the identity.
5*15=19 so 19 is in the group.
5*19=39 so that's in the group.
5*39=27
5*27=23
5*23=3
5*3=15 so that doesn't help!
15*3=45
45*5=1 so that doesn't help.
5*5=25
39*39=9
39*3=5 which doesn't help.
45*9=13
So we have {1,3,5,9,13,15,19,23,25,27,39,45}.
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