the integral of ∫{ 2x^12 + 5x^9 }dx / (x^5 +x³ +1)^2
paridhigupta1234:
(x^5 +x³ +1)^2 => (x^5 +x³ +1)^3 sorry typing error :p
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Hello pari :-)
Let I = > ∫{ 2x^12 + 5x^9 }dx / (x^5 +x³ +1)^3
I = > ∫ { 2x^12 + 5x^9 }dx / x^15 ( 1+ x^-2 +x^-5 )³
I = > ∫ {2x^-3 + 5 x^-6 }dx /( 1+x^-2 + x^-5 )³
now put 1+x^-2 + x^-5 = > t
(-2x^-3 - 5x^-6 )dx = > dt
I = > ∫dt / t³ => - 1/2t² = > -1/2( 1+x^-2 + x^-5 )² + c is our required answer
Hopes this will help you !
@ engineer gopal khandelwal
Let I = > ∫{ 2x^12 + 5x^9 }dx / (x^5 +x³ +1)^3
I = > ∫ { 2x^12 + 5x^9 }dx / x^15 ( 1+ x^-2 +x^-5 )³
I = > ∫ {2x^-3 + 5 x^-6 }dx /( 1+x^-2 + x^-5 )³
now put 1+x^-2 + x^-5 = > t
(-2x^-3 - 5x^-6 )dx = > dt
I = > ∫dt / t³ => - 1/2t² = > -1/2( 1+x^-2 + x^-5 )² + c is our required answer
Hopes this will help you !
@ engineer gopal khandelwal
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