The integral ſide for a straight conductor, carrying current, is i - 2j A-m. The
force on the conductor placed in a uniform magnetic field B = 2i - 4ſ + k ut, is
(1) 3 x 10-6N (2) V5 10-4N (3) 73 x 10-6N (4) V5 x 10-6N
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1
Answer:
zero
Explanation:
Due to anti-clockwise current, the magnetic field will be out of the plane.
& Due to clockwise current, the magnetic field will be into the plane.
they will cancel out each other
Net ∣B∣=0
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