Question

The integrating factor of (x² +y? +2x) dx +2ydy = 0 is. ?​

Answer 1

Step-by-step explanation:

( x² + y + 2x) dx + 2ydy = 0

2ydy = -( x² + y + 2x) dx

2ydy/ dx = - (x² + y + 2x)

dy/dx = -x²/ 2y + y/2y + 2x/2y

dy/dx = - x² + 2x/ 2y + 1/2

dy/dx = -( x²- 2x) / 2y + 1/2

dy/dx + ( x²- 2x) / 2y = 1/2

Here p = x² - 2x/ 2