Question

The intensity of sound from a point source is 1.0 × 10−8 W m−2 at a distance of 5.0 m from the source. What will be the intensity at a distance of 25 m from the source?

Answer 1

Explanation:

intensity of the sun from a point source is 1.0 into 10 - 8 - 2 at the distance of 5.0 metre from the source

Answer 2

The intensity at a distance of 25 m from the source is $4 \times 10^{-10} \mathrm{w} / \mathrm{m}^{2}$ the range will be 25 m away from the source.

Explanation:

Step 1:

Given data,

$\mathrm{I}_{1}=1.0 \times 10^{-8} \mathrm{W} \mathrm{m}^{-2}$

I2 = ?

r1 = 5.0 m

r2 = 25 m

I is The intensity of sound from a source point

r is distance  

Step 2:

We know that  

$1 \propto \frac{1}{r^{2}}$

$\mathrm{I}_{1} \mathrm{r}_{1}^{2}=\mathrm{I}_{2} \mathrm{r}_{2}^{2}$

$I_{2}=\frac{I_{1} r_{1}^{2}}{r_{2}^{2}}$

$\mathrm{I}_{2}=\frac{1.0 \times 10^{-8} \times 5^{2}}{25^{2}}$

$\mathrm{I}_{2}=\frac{1.0 \times 10^{-8} \times 25}{625}$

$I_{2}=\frac{25 \times 10^{-8}}{625}$

$\mathrm{I}_{2}=\frac{1 \times 10^{-8}}{25}$

$\mathrm{I}_{2}=0.04 \times 10^{-8}$

$\mathrm{I}_{2}=4 \times 10^{-10} \mathrm{w} / \mathrm{m}^{2}$

$4 \times 10^{-10} \mathrm{w} / \mathrm{m}^{2}$ The range will be 25 m away from the source .