the intensity of sound gets reduced by 20% on passing through a Wall The reduction of intensity on passing through two consecutive similar walls will be:
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Let initial intensity be x.
After passing through first wall, intensity will be x(1-0.2) as 20% is lost.
So, intensity is now 0.8x.
After passing through second wall, intensity is further decreased by 20%.
So, intensity is 0.8x(1-0.2)=0.64x
So, net decrease in intensity is (x-0.64x)*100=36% decrease.
After passing through first wall, intensity will be x(1-0.2) as 20% is lost.
So, intensity is now 0.8x.
After passing through second wall, intensity is further decreased by 20%.
So, intensity is 0.8x(1-0.2)=0.64x
So, net decrease in intensity is (x-0.64x)*100=36% decrease.
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