Question

which term of the arithmetic progression . 92,88,84,80......is 0

Answer 1

hope it helps you...!!

Answer 2

heya friends !!!✋

here is ur answer ....
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a' first term =92...

t2 =88...

d=88-92=-4....

and now,,,,,,,, .Ur tn term is given as 0 ...

so...you know tn.=a+(n-1)d....【where a=first term..d" common difference .and n = number of term.. 】

so,

tn=92+(n-1)-4

0=92-4n+4

=>96=4n

n=96/4

n=24 th term is 0.....

hope it help you.....

@Rajukumar ✋