Math, asked by manojdevarapalli, 17 hours ago

The intercept made by the circle x + y² +10x+8y-33 = 0 + on y-axis is ​

Answers

Answered by ravikupse1972
0

Answer:

...9643367890619974⁴

Answered by NirmalPandya
1

Given: Equation of the circle is  x² + y² + 10x + 8y - 33 = 0

To Find: Intercept of the circle on the y-axis

Solution:

The general equation for a circle is x² + y² + gx + fy + c = 0, where x and y are variables and g, f and c are constants.

Comparing the given equation with the general equation

g = 10 , f = 8 and c = -33

The intercept made by the circle on x-axis is2 \sqrt{g^{2} - c}

The intercept made by the circle on the y-axis is 2\sqrt{f^{2} - c}

Intercept made by the circle on y-axis = 2\sqrt{8^{2} - (-33) }

                                                                = 2 \sqrt{64 + 33}

                                                                = 2 \sqrt{97}

Therefore, the intercept made by the circle on the y-axis is 2 \sqrt{97}.                                    

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