Question

The interest for 3 years on Rs 2400 is Rs576. What is the interest on Rs4200 for 2 years at the same rate of interest

Answer 1

3147 is the answer

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Answer 2

➤ Answer :-

First of all, we should calculate the rate of interest to the first problem.

The next step is to calculate the simple intrest with obtained answer to first problem.

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➤ Given :-

Simple Interest :- ₹ 576

Principle :- ₹ 2400

Time :- 3 years

➤ To Find :-

Rate of interest to the first problem in the following question.......

➤ Formula required :-

$\longrightarrow \large \tt \orange{ \boxed{ \tt \gray { \frac{SI \times 100}{P \times T} }}}$

➤ Solution :-

Here,

SI = Simple Interest

P = Principle

T = Time

So,

$\tt \to \dfrac{576 \times 100}{2400 \times 3}$

$\tt \to \dfrac{576 \times \cancel{100}}{ \cancel{2400} \times 3} = \boxed{ \tt \dfrac{576 \times 1}{24 \times 3} }$

$\tt \to \dfrac{ \cancel{576} \times 1}{24 \times \cancel{3}} = \dfrac{192 \times 1}{24 \times 1}$

$\tt \to \dfrac{192}{24} = 8 \bf\%$

$\Huge\therefore$The rate of interest is 8 $\bf\%$.

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Now, we can find the solution to the second problem....

➤ Given :-

Principle :- ₹ 4200

Time :- 2 years

Rate of interest :- 8 $\bf\%$

➤ To Find :-

Simple interest for the second problem of the question......

➤ Formula required :-

$\longrightarrow \tt \large\orange{ \boxed{ \tt \gray{ \frac{P \times R \times T }{100} }}}$

➤ Solution :-

$\tt \to \dfrac{4200 \times 2 \times 8}{100}$

$\tt \to \dfrac{ \cancel{4200} \times 2 \times 8}{ \cancel{100}} = \boxed{ \tt42 \times 2 \times 8}$

$\tt \to 672$

$\Huge\therefore$The simple interest for the second problem is ₹ 672.