Question

The interior angles of a pentagon are in the ratio of 5:4:7:5:6.Find each angle of the pentagon.​

Answer 1

Let them be x :

5x

4x

7x

5x

6x

Step-by-step explanation:

Now

sum of the angles of pentagon = 540

so,

5x+4x+7x+5x+6x =540

27x= 540

x = 540÷27

x= 20

so,

1st angle = 5x = 5×20

= 100

2nd angle= 4x= 4×20

= 80

3rd angle= 7x= 7×20

= 140

4th angle= 5x = 5×20

= 100

5th angle= 6x = 6×20

= 120

then,

sum of all angle = 540

100+80+140+100+120 = 540