the interior angles of a triangle are(3x-10)°,(3x+10)°,(3x)°.find the angles
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As the sum of the angles is 180 in a triangle...
therefore....
3x-10+3x+10+3x=180
9x=180
x=20
therefore the angles are 50,70 and 60...
hope this helps u:p
therefore....
3x-10+3x+10+3x=180
9x=180
x=20
therefore the angles are 50,70 and 60...
hope this helps u:p
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Answered by
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3x-10 +3x + 10+ 3x= 180* ........ (< sum prop. of triangle)
=> 9x = 180* => x = 180 /9 = 20*
so ,
1) 3x - 10 = 3×20 -10 = 50*
2) 3x + 10 = 3× 20 + 10 = 70*
3) 3x = 3× 20= 60*
HOPE IT WILL HELP YOU. . . . . . . .
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! !
=> 9x = 180* => x = 180 /9 = 20*
so ,
1) 3x - 10 = 3×20 -10 = 50*
2) 3x + 10 = 3× 20 + 10 = 70*
3) 3x = 3× 20= 60*
HOPE IT WILL HELP YOU. . . . . . . .
PLZ MARK MY ANSWER AS BRAINLIEST AS SOON AS POSSIBLE! ! ! ! ! !
Plz mark my answer as brainliest. Please
Plz mark my answer as brainliest.
Plz mark my answer as brainliest. soon plz
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