The interior angles of a triangle are (3x-10)degrees,(3x+10)degree,(3x)degree find the angles
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Angle of a triangle are 3x-10°,3x+10°,3x
A/Q
(3x-10°)+(3x+10°)+3x=180° 【angle sum pr】
=> 3x+3x+3x=180° 【+10 & -10 would be subtracted】
=>9x=180°
=>x=180°/9
=>x=20°
So,the angles of the triangle
3x-10°=3×20°-10°=60°-10°=50°
3x+10°=3×20°+10°=60°+10°=70°
3x=3×20°=60°
Angle of a triangle are 3x-10°,3x+10°,3x
A/Q
(3x-10°)+(3x+10°)+3x=180° 【angle sum pr】
=> 3x+3x+3x=180° 【+10 & -10 would be subtracted】
=>9x=180°
=>x=180°/9
=>x=20°
So,the angles of the triangle
3x-10°=3×20°-10°=60°-10°=50°
3x+10°=3×20°+10°=60°+10°=70°
3x=3×20°=60°
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Answer: 90degree
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