The interior angles of triangles are (3x-10), (3x+10), (3x).Find the angles
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we can solve in this way
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we will use angle sum property which is
=>sum of interior angles of a triangle = 180
(3x-10)+(3x+10)+3x=180
9x=180
x=20
so the angles are (3x-10)=3*20-10=50
(3x+10)=3*20+10=70
3x=3*20=60 answer
=>sum of interior angles of a triangle = 180
(3x-10)+(3x+10)+3x=180
9x=180
x=20
so the angles are (3x-10)=3*20-10=50
(3x+10)=3*20+10=70
3x=3*20=60 answer
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