Question

the internal and external diameter of hollow hemispherical vessel are 16 cm and 12 cm respectively.if the cost of painting 1 cm2 of the surface area is ₹ 6.00 find the total cost of painting the vessel all over ( use 3.14)​

Answer 1

given,

internal diameter=12 cm

external diameter =16cm

radius of internal =12/2=6cm

radius of external=16/2=8cm

surface area(internal)=2πr²=2×22/7 ×6×6=2×22×6×6/7=227cm²

surface area (external)=2πR²=2×22/7 ×8×8

=2×22×8×8/7=403cm²

cost of painting = cost of internal+ cost of external+cost of the ring= 2(227)+2(403)+2(π(R²-r²)

=454+806+2(22/7(8²-6²)

=1260+44/7(64-36)

=1260+44/7(28)

=1260+44×4

=1260+176=1436 approx

because the answer come 1436 I take the next number. so it came. if u can use this process. if u want the exact value.

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