Question

the internal measure of a cuboidal room are 25 metre 48 metre 20 metre find the total surface area of the room​

Answer 1

Answer:

5320 m²

Step-by-step explanation:

Given---> Internal measures of a room are 25 m , 48m , 20 m

To find---> Total surface area of the room.

Solution---> ATQ,

Dimension of room is 25m × 48m × 20m .

Let ,

Length of room = 25m

Breadth of room = 48m

Height of room = 20 m

We , know that,

Total surface area of cuboid = 2 ( lb + bh + lh )

So , total surface area of cuboidal room

= 2 { 25 × 48 + 48 × 20 + 25 × 20 }

= 2 { 1200 + 960 + 500 )

= 2 ( 2660 )

= 5320 m²

Additional information--->

1) Volume of cuboid = l b h

2) Volume of cube = edge³

Answer 2

Given:

l=25m

b=48m

h=20m

Total surface area of cuboidal room

= 2(lb + bh+ hl)

= 2( 25m×48m + 48m×20m + 20m×25m)

= 2( 1200m² + 960m² + 500m²)

= 2 × 2660m²

= 5320 m²