Question

The internal measurements of a box are 10cm long ,8cm wide and 7 cm high.How many cubes of sides 2 cm can be put into the box

Answer 1

Answer:

length=10cm ,breadth=8cm ,height=7cm

side of cube =2cm

volume= l×b×h

10×8×7=560cm^3

volume of cube =a^3

2×2×2=8cm^3

No. of cubes required=560÷8

=70

Answer 2

Answer:

The answer of the question is:-

70 cubes of a side 2 cm can be put inside the box.

Step-by-step explanation:

From the given data in the question we can write that:-

The length(l) of the box is = 10 cm

Width(b) is = 8cm

Height(h) is = 7 cm

So the volume of the box is= l*b*h

= 560 cm³.........(1)

Now the volume of the cube is = 2³ = 8 cm³

From the question x number of cubes should be put in the box.

So the volume of the all cubes will be = 8x cm³

…..........(2)

Now from (1) or (2),

8x= 560

or, x= 70

This is the given solution of this question.

So the cube required is - 70

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https://brainly.in/question/7270694

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