Question

The internal measures of cuboidal room are 12 m × 8 m × 4m. Find the total cost of whitewashing all four walls of a room, if the cost of white washing is Rs. 5 per m^2. What will be the cost of white washing if the ceiling is also whitewashed.

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Answer 1

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♣️$\bf{\underline\green{GIVEN:}}$

⇝Length of the room = l = 12 m

⇝Width of the room = w = 8 m

⇝Height of the room = h = 4 m

⇝Cost of white washing per m² = Rs. 5

♣️$\bf{\underline\green{TO}}$$\bf{\underline\green{FIND:}}$

⇝Area of the four walls of the room.

⇝Total cost of white washing four walls of the room.

⇝Total cost of white washing the ceiling.

♣️$\bf{\underline\green{SOLUTION:}}$

⇝Area of four walls of the room =

$⟹perimeter \: of \: the \: base \: \times height \: of \: the \: room$

$⟹2(l + b) \times h = 2(12 + 8) \times 4$

$⟹2 \times 20 \times 4 = 160 \: {m}^{2}$

⇝Cost of white washing per m² = Rs. 5

⇝Hence, the total cost of white washing four walls of the room = Rs ( 160 × 5 ) = Rs 800

⇝Area of ceiling = 12 × 8 = 96 m²

⇝Cost of white washing the ceiling = Rs ( 96 × 5 ) = Rs 480.

⇝So the total cost of white washing = Rs ( 800 + 480 ) = Rs 1280.

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Answer 2

Answer:

Cost of whitewashing = Rs 1280

Step-by-step explanation:

$\blacksquare$ Given that,

Length of the room = L = 12 m

Breadth of the room = B = 8 m

Height of the room = H = 4 m

Cost of white washing per m² = Rs. 5

$\blacksquare$ We know that,

Area of the four walls of the room

= 2(LH + BH)

= 2(12 * 4 + 8 * 4)

= 2(48 + 32)

= 2(80)

= 160 m²

$\blacksquare$ Total cost of white washing four walls of the room

= 160 * 5

= Rs 800

$\blacksquare$ Area of ceiling

= 12 × 8

= 96 m²

$\blacksquare$ Cost of white washing the ceiling

= Rs 96 × 5  

= Rs 480.

$\blacksquare$ So the total cost of white washing

= Rs 800 + 480  

= Rs 1280