The internal resistance of cell using potentiometer is a. r = R (l1-l2) (b) r = R ( l1+l2) (C) r = R (l1-l2)/l2 (d) R = r (l1/l2)
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Correct option is
A
l
1
=l
2
(
R
R+r
)
The internal resistance of a cell is given as r=(
l
2
l
1
−l
2
)R
R
r
=
l
2
l
1
−l
2
∴rl
2
=Rl
1
−Rl
2
∴l
2
(R+r)=Rl
1
l
1
=l
2
(
R
R+r
)
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