Question

the interval in which function f (x) = x^2-4x+5 is increasing​

Answer 1

Answer:

2

Step-by-step explanation:

Note

${x}^{2} - 4x + 5 \\ = {x}^{2} - 4x + 4 + 1 \\ \\ = (x - 2) {}^{2} + 1$

So this function has minimum value at x=2 . [ you can also use derivative method to find critical point ). Since It's quadratic whose a > 1 , so it's a parabola facing upwards . So draw graph . As you can see it's increasing in interval (2, infinity ) .

Answer 2

Step-by-step explanation:

given :

• the interval in which function f (x) = x^2-4x+5 is increasing

to find :

• (x) = x^2-4x+5 is increasing

solution :

• To explain: f(x) = x^2 - 4x + 5.

• F'(x)=2x-4. Therefore f'(x) = 0 gives x = 2.

• Now this point x=2 divides the line into two disjoint intervals and the interval namely (2,00) is increasing on f(x).

answer:

• the answer is (2,00) increasing on f(x).