Question

the inverse function f(x)={4-(x-7)³]∧1/3 ??

Answer 1

f( x ) = { 4 - (x -7)³} ^1/3

y = { 4 -( x -7)^3}^1/3

take cube both sides

y³ = { 4 -( x - 7)³ }

y³ - 4 = -( x -7)³

4 - y³ = ( x -7)³

take cube roots both sides

( 4 -y³)⅓ = x - 7

x = ( 4 - y³)⅓ + 7

f( y ) = ( 4 - y³)⅓ + 7

put y = x in RHS then f(y) = f-1(x )

f-1(x ) = ( 4 -x³)⅓ + 7

Answer 2

Answer:

Step-by-step explanation:

Consider the function represented by the table.

For which x is f(x)?=–3

–7

–4

4

5