Question

The inverse of f(x) = [4-(x-7) ^3]^1/5 is
a) 7 + [(4-x^5)]^1/3
b) [7+[(4+x^5)]^1/3]
c) [7-[(4-x^5)]^1/3]
d) [7-[(4+x^5)]^1/3]​

Answer 1

$\huge\mathfrak\red{Answer :) }$

The inverse of f(x) = [4-(x-7) ^3]^1/5 is

a) 7 + [(4-x^5)]^1/3

b) [7+[(4+x^5)]^1/3]

c) [7-[(4-x^5)]^1/3]

d) [7-[(4+x^5)]^1/3]

Answer =[7-[(4+x^5)]^1/3]

Answer 2

Answer:

ANSWER :)

[7-[(4+x^5)]^1/3]

THANK YOU

HOPE IT HELPS.......