Chemistry, asked by chetanspurohit28, 2 days ago

The ionic radius of an anion is 2.11 Å. There of the smallest cation with ligancy 8 will be (a) 2.11 Å (b) 1.545 Å (c) 2.455 Å (d) 4.211 Å​

Answers

Answered by ayushchand1223
0

Answer:

Correct option isA

6Here using the radius ratio rule

Therefore R B R A = 1.81×10 −10 0.98×10 −10

R

B

R

A

+

= 0.54

now 0.54 lies between 0.414−0.732

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