Chemistry, asked by pravikumar, 1 year ago

The ionic radius of Cr is minimum in which of the following compounds 1) CrF3 2) CrCl3 4)Cr2O3 5)K2CrO4

Answers

Answered by kus0x45p
43

Oxidation number of Cr in options a, b, c and d are +3, + 3, + 3, + 6 respectively. In given options K2Cr2O4 has high oxidation number therefore its radii will be low. Atomic radii decreases with increase in oxidation no.
why?This is due to the fact that atomic radius increases in size with an increase of electronic energy levels. This lessens the attraction for valence electrons of other atoms, decreasing reactivity.

Answered by madhurihippargi2000
2

Answer:

ans no 4) correct hai....lekin apaka serial number galat hai

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