The ionic radius of Cr is minimum in which of the following compounds 1) CrF3 2) CrCl3 4)Cr2O3 5)K2CrO4
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Oxidation number of Cr in options a, b, c and d are +3, + 3, + 3, + 6 respectively. In given options K2Cr2O4 has high oxidation number therefore its radii will be low. Atomic radii decreases with increase in oxidation no.
why?This is due to the fact that atomic radius increases in size with an increase of electronic energy levels. This lessens the attraction for valence electrons of other atoms, decreasing reactivity.
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ans no 4) correct hai....lekin apaka serial number galat hai
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