Chemistry, asked by choudharymuneeb75003, 10 months ago

The ionic radius of M²⁺ ions.

Solution:

Let the edge length of the unit cell of the lattice be a
The formula  for density d = (Z*m)/(a³*NA) ⇒ a = ∛((Z*m)/(d*NA))
Hence, the edge length a = ∛m A⁰
Now, in FCC r(M²⁺) + r(X²⁻) = a/2 ⇒ r(M²⁺) = (0.5*∛m - 1.08) A⁰
Answer:

The ionic radius of M²⁺ ions = (0.5*∛m - 1.08) A⁰
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Answered by khushbujawaliya
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Answer:

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Explanation:

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