The ionization potential of lithium and potassium are 5.4 and 4.3ev. What do you predict for the i.p of Na?
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ionisation potential is the energy required to remove an electron
lithium has to loose 1 electron
it's ionisation potential is 5.4 ( given)
so in the same way Na (sodium ) has to loose an electron to become stable
so the lithium Nd sodium has nearly same ionisation potential but some difference because of p shell in Na
so ionisation potential of Na -sodium is 5.139
lithium has to loose 1 electron
it's ionisation potential is 5.4 ( given)
so in the same way Na (sodium ) has to loose an electron to become stable
so the lithium Nd sodium has nearly same ionisation potential but some difference because of p shell in Na
so ionisation potential of Na -sodium is 5.139
Answered by
3
Answer:
Because ionization potential is the energy required to remove the outer most electron of a neutral gaseous atom.
size inversely proportional to IP
size Li<Na<K
so IP Li>Na>K
5.4ev>Ip of Na>4.3ev
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