Question

the irrational number 7/3+√n when rationalized become 3-√n. the value of n​

Answer 1

Step-by-step explanation:

Given :-7/3+√n=3-√n

To find:-n=?

Solution:- 7/3+√n×3-√n/3-√n

==>7(3-√n)/3.sq.-(√n)sq.

==>7(3-√n)/9-n=3-√n

==>7/9-n=1

==>9-n=7

==>n=9-7=2

hope it will help you dear