Physics, asked by UnknownCrasher1711, 11 months ago

the isotope of carbon 14 has Half Life 5730 years if the ratio of C14 TO C 12 is 1.3Ã10 ^-13 in a wood sample, then find activity of sampleof 1g of wood

Answers

Answered by sparshdaisy
24

Answer:

0.02 Bq

Explanation:

Activity = λN= ( ln2 / T half) N

N = {(6.023*10^23)/12}*1.3*10^-13=5.6 * 10 ^9

= (0.693/5750 * 3.15*10^7)*5.6*10^9= 0.02Bq

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