Question

The IUPAC name of the following compound is
OH
(a) 4-hydroxy - 5 - methyl - hexan - 2- one
(b) 2 - oxo - 5-methyl - hexan -4 - ol
(0) 3 - hydroxy - 2-methyl - hexan - 5 - one
(d) 5 - oxo - 2-methyl - hexan - 3 - ol​

Answer 1

Given to find the IUPAC name of the compound:-

The IUPAC name of the given compound is 4-hydroxy-5-methyl-hexan-2-one

Explanation:-

By observing the compound,

We can say that 3 substituents are present .They are Alcohol, Ketone, Methyl .

We also know that,

Alcohol and ketone are functional group .

According to Functional group order,

Ketones > Alcohols.

So, We are used to write now Alcohol as substituent (prefix) is hydroxy.

Ketone is taken as suffix (oxo or one)

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Now, selecting the parent chain :-

Containing more subtituents and more no.of carbons is taken as parent chain.

Longest Parent chain has 6 carbons

Root word is hex

Refer the attachment.

So, now

We have to give numbering for the substituents,

If we give from left-right

Ketone => 2

Alcohol => 4

Methyl => 5

If we give from right-left

Ketone => 5

Alcohol => 3

Methyl => 2

So, we have to follow numbering from left-right As ketone gets lowest number

Now writing the IUPAC name:-

By alphabetical order :-

H ydroxy , M ethyl

We have to write 1st Hydroxy .

4-hydroxy, 5-methyl hexan-2-one

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