Question

The IUPAC name of the given compound is:
O 5, 6-dimethyloct-6-ene-2-yne
O 3,4-dimethyloct-2-ene-6-yne
O 5, 6-dimethyl oct-2-yne-6-ene
O 3,4-dimethyl-2-octane-5-yne

Answer 1

Answer:

B) 3,4-dimethyloct-2-ene-6-yne

Explanation:

Step 1:

Choose the longest carbon chain. In this molecule, there are eight carbon atoms in the parent chain.

Step 2:

Select your preference.

A double bond is given priority over a triple bond, so the carbon atom having a double bond should have a lower value.

Methyl groups should also be named on carbon atoms having lower values. We will call them 3 and 4 instead of 5 and 6.

Answer 2

Answer:

$3,4-dimethyloct-2-ene-6-yne$ is the correct option.

Summary of rules involved in IUPAC nomenclature

Determine the carbon atom chain with the longest length. Find the longest continuous carbon chain and give it a name. Identify and name the many groups that are connected to this chain.

The substituents' names and positions. The relative positions of two or more substituents on a benzene molecule must be numbered. Position 1 is given to the first substituent alphabetically, and the ring is numbered in a circle to give the other substituents the lowest possible number (s).

Starting at the end closest to a substituent group, number the chain sequentially.

Give each substituent group a number and a name that corresponds to its placement.