The k.E energy of an object with a velocity of 5ms is 25j what will be its k.E energy when its velocity is doubled
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Expression for kinetic energy is
m = Mass of the object
v = Velocity of the object = 5 ms-1
Given that kinetic energy, Ek= 25 J
If the velocity of an object is doubled, then its kinetic energy becomes 4 times the original value, because it is proportional to the square of the velocity. Hence, kinetic energy = 25 × 4 = 100 J.
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