Question

The K. E of bullet of mass 500 gm moving at a speed of 200 ms-'is
(A) 250J
(B) 125J
(C) 25000(D) 10000
​

Answer 1

Answer:

Given,

mass (m) = 500 gm = 0.5 kg

velocity (v) = 200 m/s

we know,

K.E = 1/2* mv²

= 1/2 ×0.5 ×(200)²

= 1/2×0.5×400

= 1/2× 200

=100 kg m/s

Answer 2

Answer:

K.E of the bullet is 10000 J

Explanation:

mass=500g=0.5kg,velocity=200m/s

then,

K.E=1/2mv^2

=1/2*0.5*200*200

=50*200=10000J