Question

The velocity-time graph of a moving particle is given
below. The acceleration of the particle at t = 5 s will be

Answer 1

Answer:

a=v-u/t

a=4 - 0 /5

a=4/5

a=0.8 m/s^2

Answer 2

acceleration of   the particle at t = 5 s will be 0 m/s²

Explanation:

acceleration of the particle  = dv/dt

=> slope of v-t at any point will give acceleration at that point

at t = 5s  Slope of graph will be

Slope between time 2s &  6s   ( is same)

Slope  =  (4 - 4)/(6 - 2) = 0/4 = 0

Hence acceleration of   the particle at t = 5 s will be 0

Average acceleration from 0 to 5 secs would be

= (4 - 0)/(5 -0) = 4/5  m/s²

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