Question

the KE of an electron in an orbit of radius,r of Li2+ ion is

Answer 1

K.E. of an atom in terms of radius is,

$= \frac{z {e}^{2} }{2r}$

for Li+2 ion z=3

then K.E.

$= \frac{3 {e}^{2} }{2r}$

where e is the charge of electron