the kinetic energy of 2 moles of a gas speed at 27° in calories
ketangoyal:
find kya krna h
kinetic energy
Answers
Answered by
6
hey ur answer is,
KE= 3/2nRT
. =3/2x2x2x300
. =1800 cal
here n its number of moles.=2
R is gas constant=2 cal/K
T is temp=300K
KE= 3/2nRT
. =3/2x2x2x300
. =1800 cal
here n its number of moles.=2
R is gas constant=2 cal/K
T is temp=300K
solve the second equation that i gave using temp in kelvin u will get the answer.
hope it helped. mark the answer brainliest
answer ni pta
kiska answer
solving as per the question in comment u get v1/v2 = 0.644
tereko ata h to puchta kyo h
pagal to ni h na
abey dhakkan vo kisi ar ne poocha tha
i answered
poore comments padh lene chaiye before commenting
Similar questions