the kinetic energy of a body is K if one fourth of its mass is removed and velocity is doubled it's new kinetic energy is
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Answered by
37
K=mv^2/2
now
new mass=m-1/4m=3/4m
velocity= 2v
new k=3/4m(2v)^2/2
=3 mv^2/2
=3K
kinetic energy gets tripled
now
new mass=m-1/4m=3/4m
velocity= 2v
new k=3/4m(2v)^2/2
=3 mv^2/2
=3K
kinetic energy gets tripled
Answered by
12
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