Question

The kinetic energy of a body of mass 20gm moving with a velocity of 180 m/s is ?​

Answer 1

Given ,

• Mass of body (m) = 20 gm or 2 × (10)^(-2) kg

• Velocity of body (v) = 180 m/s

We know that , the kinetic energy of body is given by

$\large { \boxed{ \sf{Kinetic \: energy = \frac{1}{2} m {(v)}^{2} }}}$

Thus ,

$\sf \mapsto Kinetic \: energy = \frac{1}{2} \times 2 \times {(10)}^{ - 2} \times {(180)}^{2} \\ \\ \sf \mapsto Kinetic \: energy = 32400 \times {(10)}^{ - 2} \\ \\ \sf \mapsto Kinetic \: energy =324 \: \: joule$

$\sf \therefore \underline{The \: kinetic \: energy \: of \: body \: is \: 324 \: J}$

Answer 2

Explanation:

Mass of body (m) = 20 gm or 2 × (10)^(-2) kg

Velocity of body (v) = 180 m/s

We know that , the kinetic energy of body is given by

\large { \boxed{ \sf{Kinetic \: energy = \frac{1}{2} m {(v)}^{2} }}}

Kineticenergy=

2

1

m(v)

2

Thus ,

\begin{gathered}\sf \mapsto Kinetic \: energy = \frac{1}{2} \times 2 \times {(10)}^{ - 2} \times {(180)}^{2} \\ \\ \sf \mapsto Kinetic \: energy = 32400 \times {(10)}^{ - 2} \\ \\ \sf \mapsto Kinetic \: energy =324 \: \: joule\end{gathered}

↦Kineticenergy=

2

1

×2×(10)

−2

×(180)

2

↦Kineticenergy=32400×(10)

−2

↦Kineticenergy=324joule

\sf \therefore \underline{The \: kinetic \: energy \: of \: body \: is \: 324 \: J}∴

Thekineticenergyofbodyis324J