Question

the kinetic energy of a hydrogen molecule travelling at 1900m/s​

Answer 1

Answer:

mass of 1mole H molecule = 2g

mass of 1 molecule = 2/(6×10²³) = 10/3 ×10^-²² g = 10/3× 10^-24 kg

so, K.E = 1/2*(m)*(v²) = 1/2*(10/3× 10^-24 kg)×(1900)² = 601 × 10^-24 × 10^4 = 6.01×10^-18J

Explanation

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