The kinetic energy of a particle moving along a straight line varies uniformly with respect to time. The force acting on the particle is
[A]
constant
[B]
proportional to velocity
[C]
inversely proportional to velocity
[D]
inversely proportional to square root of velocity
deepas05122001:
plz answer
its urgent
but the answer given is C
bt i dont know the explanation
Answers
Answered by
14
Answer is C.. As here the foce i.e. Kinetic Energy is acting according to the inversely proportion of the velocity. Hope I helped u... Plz mark as the BRAINLIEST answer...
can you explain in detail plz
i am unable to understand
Sorry there is a connection problem..
anyone else who could explain
Answered by
17
K.E = 1/2 mv² = 2k•E/V²
F = m×a a = V/t
F = mv/t
F = 2•K•E / V² × V / t
F = 2• K•E/ Vt
F =k/v
Wait let me make it more clear
K.E = 1/2 mv² = 2k•E/V²
F = m×a a = V/t
F = mv/t
F = 2•K•E / V² × V / t
Therefore, F is inversely proportional to 1/V
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