Question

The kinetic energy of a projectile at the highest point of its path, which is projected at an angle of 30° from the ground is: A) 6/4 of initial K.E 3/4th of initial K.E B) Zero D) None of these​

Answer 1

Answer:

Let A be the initial point of projection and B be the point of maximum height

K.E

B

=

2

1

mv

2

cos

2

θ

K.E

A

=

2

1

mv

2

Now, K.E

A

=

4

3

K.E

B

⇒cosθ=

2

3

⇒θ=30