Chemistry, asked by Anjnak1568, 1 year ago

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a₀ is Bohr radius] :
(a) \frac{h^2}{4\pi^2ma_0^2}
(b) \frac{h^2}{16\pi^2ma_0^2}
(c) \frac{h^2}{32\pi^2ma_0^2}
(d) \frac{h^2}{64\pi^2ma_0^2}

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