The kinetic energy of an object of
H-W mass, m moving with a velocity
of 5 msis 25 J. What will be its
kinetic energy when its velocity
is doubled? What will be its
kinetic energy when its velocity
is increased three times?
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Answer:
225 J
Explanation:
KINETIC ENERGY of the object = 25 J.
So,
25=1/2*m*(5)
Therefore,m=2 kg.
Now, when the velocity is doubled, velocity
becomes=2*5=10 m/s(ms-7)
So,
K.E.=1/2*2*(10)2 =100 J.
Now,when the velocity is increased three times, the velocity will be=3*5=15m/s
Therefore,K.E.=1/2*2*(15)² = 225 J.
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