Question

The Kinetic energy of an object of mass 'm' moving with a velocity 5ms-1 is 25J what will be its kinetic energy when its velocity is doubled? What will be kinetic energy when its velocity is increased three times.

Answer 1

Answer:
Expression for kinetic energy is
m = Mass of the object

v = Velocity of the object = 5 ms-1

Given that kinetic energy, Ek= 25 J



(i) If the velocity of an object is doubled, then its kinetic energy becomes 4 times the original value, because it is proportional to the square of the velocity. Hence, kinetic energy = 25 × 4 = 100 J.

(ii) If velocity is increased three times, then its kinetic energy becomes 9 times the original value, because it is proportional to the square of the velocity. Hence, kinetic energy = 25 × 9 = 225 J.

Answer 2

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ANSWER :

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The mass of the object, m = m kg

The speed of the object, v = 5 m/s

The Kinetic Energy, K.E = 25 J

We know that ,

$kinetic \: energy = \frac{1}{2} mv ^{2}$

From this ,,,

Kinetic Energy ,K.E = 1/2 × m× (5)^2

25 = 1/2 × m × 25

m = 2 kg

(i) Now the Velocity of the object is doubled,,

v2 = 2v1

= 2( 5)

v2 = 10 m/s

Kinetic Energy, K.E = 1/2 × m × (v2)^2

= 1/2 × 2 × 10^2

= 100 J

The Kinetic Energy is 100 J.

(ii) Now the velocity is tripled ,,

v3 = 3v1

= 3 ( 5)

v3 = 15 m/s

Kinetic energy, K.E = 1/2 × m × (v3)^2

= 1/2 × 2 × (15)^2

= 225 J

The kinetic energy is 225 J

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