The width of each of the continuous classesin frequency dustribution is 5and the lower class limit of the lowest class is 10 the upper class limit of the highest class is
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Width of five continuous classes 5 and the lower class limit of lowest class = 10
The upper limit of highest class = lower limit of lowest class + Number of continuous classes × width of each class
= (10 + 5 × 5)
= 10 + 25 = 35.
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The upper limit of highest class = lower limit of lowest class + Number of continuous classes × width of each class
= (10 + 5 × 5)
= 10 + 25 = 35.
plzz mark as brainliest answer !!!
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